12c^2+17c-40=0

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Solution for 12c^2+17c-40=0 equation: 


Simplifying
12c2 + 17c + -40 = 0

Reorder the terms:
-40 + 17c + 12c2 = 0

Solving
-40 + 17c + 12c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-8 + -3c)(5 + -4c) = 0


Subproblem 1
Set the factor '(-8 + -3c)' equal to zero and attempt to solve:

Simplifying
-8 + -3c = 0

Solving
-8 + -3c = 0

Move all terms containing c to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + -3c = 0 + 8

Combine like terms: -8 + 8 = 0
0 + -3c = 0 + 8
-3c = 0 + 8

Combine like terms: 0 + 8 = 8
-3c = 8

Divide each side by '-3'.
c = -2.666666667

Simplifying
c = -2.666666667

Subproblem 2
Set the factor '(5 + -4c)' equal to zero and attempt to solve:

Simplifying
5 + -4c = 0

Solving
5 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -4c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -4c = 0 + -5
-4c = 0 + -5

Combine like terms: 0 + -5 = -5
-4c = -5

Divide each side by '-4'.
c = 1.25

Simplifying
c = 1.25
Solution
c = {-2.666666667, 1.25}

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